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Hydrology |Chapter: Introduction | MCQ Practice | Section-3

Precipitation Measurement

>> Chapter-2: Precipitation Measurement


Practice Set-1


1. An ombrometer (pluviometer) measures:





Ombrometer Function

Correct Answer: b) Rainfall depth

An ombrometer (also called pluviometer) is the scientific name for a rain gauge. It measures the depth of liquid precipitation over a specified time period, typically in millimeters.


2. Humidity is measured by a:





Humidity Measurement

Correct Answer: a) Hygrometer

A hygrometer measures atmospheric humidity. Other instruments:
- Hyetometer: Measures rainfall (obsolete term)
- Hydrometer: Measures liquid density
- Pyrheliometer: Measures solar irradiance


3. For a storm, if the highest rainfall (Pₘ) and average rainfall (Pₐ) are related as Pₘ/Pₐ = K exp(-A), this represents:





Rainfall Spatial Distribution

Correct Answer: b) Areal reduction factor

This empirical formula describes how point rainfall (Pₘ) reduces to areal average rainfall (Pₐ) with increasing area (A). K is a regional constant.


4. In a rain gauge network, Indian standards recommend:





IS 4987 Recommendations

Correct Answer: d) 10% recording-type gauges

Indian Standard IS 4987 recommends:
- Hills need denser networks than plains (1/130 km² at 1000m elevation)
- 10% of gauges should be recording type
- Plains: 1 gauge per 250-500 km²


5. The number of rain gauges required for a 1000 km² plain area as per Indian standards is:





Gauge Density Calculation

Correct Answer: d) 4

For plains (250-500 km² per gauge):
1000 km² ÷ 250 km²/gauge = 4 gauges
This ensures adequate spatial coverage for accurate areal rainfall estimation.


6. An isopluvial line joins points with equal:





Isopluvial Definition

Correct Answer: a) Rainfall

Key distinctions:
- Isohyet: Single storm rainfall
- Isopluvial: Mean annual rainfall
- Isonif: Snowfall
- Isohel: Sunshine duration


7. Station X (annual avg. rainfall = 120 cm) was inoperative during a storm. Surrounding stations (A=100 cm, B=90 cm, C=110 cm) recorded 9.2 cm, 8.1 cm, and 10.5 cm respectively. The missing storm rainfall at X is:





Normal Ratio Method Calculation

Correct Answer: b) 11.2 cm

Calculation steps:
1. Compute weighted ratios:
(120/100)×9.2 = 11.04
(120/90)×8.1 ≈ 10.8
(120/110)×10.5 ≈ 11.45
2. Average: (11.04 + 10.8 + 11.45)/3 ≈ 11.1 cm
Rounded to 11.2 cm


8. A 4-hour hyetograph with varying time intervals has ordinates (mm/hr):

0-30 min: 72 | 30-60 min: 84 | 1-2 hr: 60
2-2.5 hr: 54 | 2.5-3 hr: 78 | 3-4 hr: 42





Hyetograph Calculation

Correct Answer: c) 234 mm

Breakdown:
1. First hour (2 intervals × 30 min):
(72+84)×0.5 = 78 mm
2. Second hour (1 interval × 60 min):
60×1 = 60 mm
3. Third hour (2 intervals × 30 min):
(54+78)×0.5 = 66 mm
4. Fourth hour (1 interval × 60 min):
42×1 = 42 mm
Total = 78 + 60 + 66 + 42 = 234 mm



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